y^2+5y+3/y^2+y+2=3/2

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Solution for y^2+5y+3/y^2+y+2=3/2 equation: 



y^2+5y+3/y^2+y+2=3/2

We move all terms to the left:

y^2+5y+3/y^2+y+2-(3/2)=0



Domain of the equation: y^2!=0

y^2!=0/

y^2!=√0

y!=0

y∈R



We add all the numbers together, and all the variables

y^2+5y+3/y^2+y+2-(+3/2)=0

We add all the numbers together, and all the variables

y^2+6y+3/y^2+2-(+3/2)=0

We get rid of parentheses

y^2+6y+3/y^2+2-3/2=0

We calculate fractions

There is no solution for this equation

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